Vudujin
Smash Lord
[skwair]
Sirkul gets the Skwair.
Sirkul gets the Skwair.
Welcome to Smashboards, the world's largest Super Smash Brothers community! Over 250,000 Smash Bros. fans from around the world have come to discuss these great games in over 19 million posts!
You are currently viewing our boards as a visitor. Click here to sign up right now and start on your path in the Smash community!
Takis car is
Me Taki Johny amine and Davey
I believe tedium is going with Slamus
Erie guys. Roh and Travis and Jacob? Are going together.
Leaving chris aaron rob and D.A. SHUFFLA
good teenagers take off your clothes... lol can't beat this, though you gotta learn your tangled stuffI will sing disney
loudly
and I probably wont have clothes on
****in' ruining it. =(-30
10orderofoperations
maybe we can get something together at the crib tomorrow* for anyone in the area that actually wants to smash. it's a win-win. on one hand, we get to practice. on the other hand, we get to be lazy and not actually have to go anywhere.Oh yeah. Also ambix. Lol sorry to many smashers.
Also, call it what you want but im probably not gonna come to duq Friday if were all playing cards.. Last time everyone played cards and the only people I played were Taki Johny and Davey.. And like one match with Gerald. But I play them all the time.
I prefer the proof I recently learned that there exist two irrational numbers a and b such that a^b is rational.Emma Watson's Boyfriend said:0.999999.... == 1
Discuss.
The ****in' truth.Proofs are dumb
What did you just post from?The ****in' truth.
Music is the only worthwhile branch of mathematics.
Neither of the examples he gave are actually valid when considering a proof. 1 =/= .9999... 1 is approximately .999... they are not numerically equivalent. They proof using 's' only works if you already assume that you believe .99999...=1, otherwise it can be contradictory. Let's look at his second example but instead use another non-ending number pi. Calculators tell us pi=3.141592654, rounding the last digit up (creating an approximation of pi). But in reality pi=3.1415926535... There between these two numbers is 0.0000000005, when is should be 0 if they were both truly pi. But as we know from grade school rounding numbers changes the number. So if you want to say .9999...=1 then you will inevitably need to round .999... much like you do with pi, thus changing the number creating an approximation of the real number. Thus, .999.. is a real number and must be exclusively different from 1, another real number.
There exists proofs aren't really the coolest because you only need to show it for 1 case. This same statement was also proven using log(4) and sqrt(10), which is far more direct. [sqrt(10)]^[log(4)]=2I prefer the proof I recently learned that there exist two irrational numbers a and b such that a^b is rational.
Let both a and b be √2. Then we raise √2^(√2). If it is rational, we're done. If it isn't rational, then we let a = √2^(√2), and raise this to √2. We can multiply the powers which gives us √2 * √2 = 2.
This leaves us with √2^2 = 2, which is rational.
The best part is we don't even know which of these two situations works because we don't know the rationality of √2^(√2), but the proof guarantees that at least one of them works!
THIS IS BULL****!i got a 3 a 4 a king a six and an ace. . . . I win!!!!!
Hey wait?! Why do you win?
Because i win.
This song is pro.