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- Aug 7, 2012
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- ScoliosisxJones
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Yesterday I mentioned the theory that, because of Smashdown, the final roster (save for 2/3 of the Pokemon Trainer, and all 3 Mii Fighters) would have to be a number divisible by 2, 3, and 4. This would mean the roster would have to be a number that is a sum of 12. (12, 24, 36, 48, 60, 72, 84, 96, etc)
Here's my question though: Does anyone know if Smashdown must be played with 4 people? Or if it's filled in by CPUs? if it always has 4 players regardless, then that would hypothetically lead to more diverse roster totals.
The only reason I'm hinging on this theory is that Smashdown wouldn't function properly if it wasn't evenly divided among all three numbers (2, 3, 4). If anybody has any thoughts on that I'd be very appreciative of it!
Here's my question though: Does anyone know if Smashdown must be played with 4 people? Or if it's filled in by CPUs? if it always has 4 players regardless, then that would hypothetically lead to more diverse roster totals.
The only reason I'm hinging on this theory is that Smashdown wouldn't function properly if it wasn't evenly divided among all three numbers (2, 3, 4). If anybody has any thoughts on that I'd be very appreciative of it!