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1 = 2 ?!

AltF4

BRoomer
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Mathematics is undeniable!

Read at your own danger: The universe might explode!!!
If you're a math major, just smile and nod

NEW ONE
x^2 + x + 1 = 0
x^2 = -x - 1
Divide by x (assume x is not 0)
x = -1 - 1 / x

Substituting the last expression for x in the original equation we get:
x^2 + ( x ) + 1 = 0
x^2 + ( -1 - 1 / x ) + 1 = 0
x^2 + ( -1 / x) = 0
x^3=1
x=1

Substituting x=1 in the original equation yields:
1^2 + 1 + 1 = 0
3 = 0


a = b
a^2 = a*b
a^2-b^2 = a*b-b^2
(a+b)(a-b) = b(a-b)
(a+b) = b
a+a = a
2a = a
2 = 1


-1 = (-1)^3 = (-1)^ (6/2) = ((-1)^6)^(1/2) = 1^(1/2) = 1


-20 = -20
25 – 45 = 16 - 36
5^2 – 5*9 = 4^2 – 4*9
5^2 – 5*9 + 81/4 = 4^2 – 4*9 + 81/4
(5 – 9/2)^2 = (4 – 9/2)^2
(5 – 9/2) = (4 – 9/2)
5 = 4


Let x = 1 – 1 + 1 – 1 + 1 …
X = (1 – 1) + (1 – 1) + (1 – 1) +…
X = 0 + 0 + 0 + …
X = 0
Let x = 1 – 1 + 1 – 1 + 1 …
X = 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) …
X = 1 + 0 + 0 + 0 + 0…
X = 1
Thus,
1 = 0


Let x = 1 + 1 + 1 + … + 1 ( x many times)
Multiply by x
x^2 = x + x + x + … + x
Take the derivative of both sides
2x = 1 + 1 + 1 + … + 1
2x = x
2 = 1


a + b = c
4a - 3a + 4b - 3b = 4c - 3c
4a + 4b - 4c = 3a + 3b - 3c
4 * (a+b-c) = 3 * (a+b-c)
4 = 3


And probably more to come as I remember them.


Source: Wikipedia for some. Most I just remember. I tutor math and I like showing my students these.
 

flicker

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A dif 1 = 0 than yours i meant.

wait, isn't your first part of the 1 = 0 wrong? because you cant just assume parenthesis. you have to go step by step meaning the first two numbers then yu completely write it out again doing the first two numbers in that equation (formally 1and2 and 3.)
 

Lixivium

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Edit: Removed by request of topic poster

Don't trust those equations! They lie!!
 

Tom

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Here are a few proofs that everyone will enjoy! Enlightening!
If you're a math major, just smile and nod
Off the top of my head: (no references)

#1:
You can't divide by (a - b) because (a - b) = zero!

#4:
You can't forget about the dx after you take the derivative (Chain Rule FTW). The only way to get rid of it is to divide both sides by dx, which is zero again!
Do what the good man says, just smile and nod. :)

I love proofs like these, especially when you are able to show them to someone and then watch them figure them out.
 

AltF4

BRoomer
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and on -1 and 1 you can't speparate a power like that. because instead of doing a number to the power of three you are doing a number to the power of 6 then 1/2.
What are you talking about?! The math is undeniable! You can't seriously think you can win versus math!!!

Yes, actually you can separate the powers like that. .
 

Jayferd

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Berkeley/Sacramento
Here are a few proofs that everyone will enjoy! Enlightening!
If you're a math major, just smile and nod

Read at your own danger: The universe might explode.

a = b
a^2 = a*b
a^2-b^2 = a*b-b^2
(a+b)(a-b) = b(a-b)
(a+b) = b
a+a = a
2a = a
2 = 1
lolz, if a = b, then a-b = 0, so...
*smiles and nods*
 

Xsyven

And how!
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Look at me! I'm cool because I use spoiler tags!

Math is broken! I seriously can't look at it and just smile like you guys do. I really hate math.
 

Lixivium

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Integers are DEFINITELY differentiable. The derivative of any integer (even infinity) is zero!
 

AltF4

BRoomer
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1st: Infinity is not an integer. 2nd The derivative of any CONSTANT is zero, not the derivative of any integer. 3rd In order to take the derivative of a function, it must be continuous. The function f(x) = x where x is an integer is not continuous thus not diferentiable
 

commonyoshi

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Math after 7th grade is stupid. >_<
This is the first equation.
a^2-b^2 = a*b-b^2
(a+b)(a-b) = b(a-b)
Is this even legal? I dont know any mathemagical mumbo jumbo, but you can replace the "(a+b)" with anything you want like so because it would still end up being 0:

(100000a+b)(a-b)=b(a-b)
(100000a+b)=b
100000a+a=a
1000001=1

You cant cross cancel 0, can you? >_>
 

AltF4

BRoomer
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That's just some basic 9th grade factoring. Nothing special or incorrect with the lines you've quoted me on.

Left hand side is the "Difference of perfect squares"

Right hand side just takes out a b.

Edit: ZOMG You can't argue with my proofs! They are perfect! Are you some kind of math-noob?! Mwua ahahaha!
 

Lixivium

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Sorry, I meant to say "Constant", not "Integer"

edit: Nevermind about the continuity. I gotcha, but you can still take derivatives of discontinuous functions. It's just that you have a separate derivative for each interval, and in this case they all happen to be zero.
 

Sinz

The only true DR vet.
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Just smiling and nodding at mistakes.
 

AltF4

BRoomer
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Sorry, I meant to say "Constant", not "Integer"

And how is f(x) = x, where x is an integer, not continuous? An integer is still a constant, and the derivative of a constant is still zero.
Go and plot it on a calculator. It's not continuous.

Wow. This is cool. About when do you start learning this? (I'm going to 1st year HS, taking Geometry btw)
Maybe about Algebra 2 (Some schools call it Algebra 3-4). Some of the proofs require calculus though. Although they don't exactly teach you this in class.
 

WFL

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I showed these to about 10 different people during the school year and maybe 1 or 2 figured out that I was dividing by 0. The others were saying how does ab equal a^2 or how do you know a=b. If you ever read the book "Biography of Zero" you'll see this and a lot of other math tidbits. It also proves Winston Churchill is a carrot.
 

mark.

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I'm mark, and i like this cookie monsta.
1. -1/1 = 1/-1
2. Taking the square root of both sides: (-1/1)^.5=(1/-1)^.5
3. Simplifying: (-1)^.5/(1)^.5=(1)^.5/(-1)^.5
4. or, i/1=1/i
5. therefore, i/2=1/(2i)
6. i/2 + 3/(2i) = 1/(2i) + 3/(2i)
7. i (i/2 + 3/(2i) ) = i ( 1/(2i) + 3/(2i) )
8. (i^2)/2+(3i)/2i=i/(2i)+(3i)/2i)
9. (-1)/2+3/2=1/2+3/2
10. 1=2

i'm 15. cut me some slack plx i tried ;x LOL
 

pikachun00b7

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Since I'm 13, no slack for you!

1. -1/1 = 1/-1
2. Taking the square root of both sides: (-1/1)^.5=(1/-1)^.5
3. Simplifying: (-1)^.5/(1)^.5=(1)^.5/(-1)^.5
n00b! SQRT-(a/b) does not equal SQRT- A/ SQRT-B

4. or, i/1=1/i
5. therefore, i/2=1/(2i)
You are getting your fractions wrong.
If a/xb=b/xa then b=a. However, i does not equal +1.


10. 1=2
..................................................................................................

i'm 15. cut me some slack plx i tried ;x LOL

Phailure!
 

Lixivium

Smash Champion
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3. Simplifying: (-1)^.5/(1)^.5=(1)^.5/(-1)^.5
n00b! SQRT-(a/b) does not equal SQRT- A/ SQRT-B
That's not what he did. The square root of a fraction is equal the sqrt of the numerator over the sqrt of the denominator. That's perfectly legal.

pikachun00b7 said:
4. or, i/1=1/i
5. therefore, i/2=1/(2i)
You are getting your fractions wrong.
If a/xb=b/xa then b=a. However, i does not equal +1.
Uh, no he's not. He just divided both sides by 2.

Edit: He didn't screw up step 3 or step 5. But there is one equation that's blatantly wrong.

If you're 13 why do you have Faraday's Law in your signature?
 

AltF4

BRoomer
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That's not a bad one, Mark. It's pretty convincing and looks sound at a first read, which is all that matters. Give him some slack indeed.

Maybe I'll make a guide on how to write your own 1=2 proofs.

PS: Faraday's Law lol.
 
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