SuSa
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Link to original post: [drupal=3743]0.999... = 1[/drupal]
I've seen this debate on many a forum. Let's see how educated SWF is about it. I want this in blogs instead of the debate hall because of what this really turns into.....anyways let's begin.
First I will use a mathematical proof to prove that 0.999... (where 9 is repeated into infinity) is equivalent to 1.
If 1/3 = 0.333...
And 0.333... * 3 = 0.999...
And 1/3 * 3 = 1
Then 0.999... = 1
Now here is where lies the debate...
If 1/3 is not actually equivalent to 0.333... it is approximate. What is it approximately?
Else 1/3 is equivalent to 0.333... and cannot ever be exactly 1/3rd of an object. All three pieces would have to be finite, and one piece must be larger. Example:
0.333...
0.333...
0.333...4 (infinitely as small as the previous two, but ending in 4)
What do you think? I hold the personal opinion that you cannot actually divide 1 by any prime number that ends in a repeating decimal. One piece would always have to be just that much larger. Therefore 1/3 and other such division by prime numbers only serve a "practical" purpose. Such as I can say I can take 6' and divide it into 3 equal groups of 2'.
The counter argument to this is the following:
It is impossible to show 1/3 in a decimal form. We simply do not have a way to write it. It exists, however we approximate to 0.333...
I've seen this debate on many a forum. Let's see how educated SWF is about it. I want this in blogs instead of the debate hall because of what this really turns into.....anyways let's begin.
First I will use a mathematical proof to prove that 0.999... (where 9 is repeated into infinity) is equivalent to 1.
If 1/3 = 0.333...
And 0.333... * 3 = 0.999...
And 1/3 * 3 = 1
Then 0.999... = 1
Now here is where lies the debate...
If 1/3 is not actually equivalent to 0.333... it is approximate. What is it approximately?
Else 1/3 is equivalent to 0.333... and cannot ever be exactly 1/3rd of an object. All three pieces would have to be finite, and one piece must be larger. Example:
0.333...
0.333...
0.333...4 (infinitely as small as the previous two, but ending in 4)
What do you think? I hold the personal opinion that you cannot actually divide 1 by any prime number that ends in a repeating decimal. One piece would always have to be just that much larger. Therefore 1/3 and other such division by prime numbers only serve a "practical" purpose. Such as I can say I can take 6' and divide it into 3 equal groups of 2'.
The counter argument to this is the following:
It is impossible to show 1/3 in a decimal form. We simply do not have a way to write it. It exists, however we approximate to 0.333...