Let's do some math!! Possible matches!!

[MorpheusVGX]

How many possible matches can we have on brawl? Singles, triples, doubles and 4 player FFA?

I will be considering 39 characters.
I will do the math on the singles: Each character can fight against all other 38 and against himself. As you move with each character, you have one less to consider, so the math is:

39 + 38 + 37 + 36 etc etc . The result is 780. Wow, that is a lot. 780 possible character combinations 1 vs 1.

Other calculations will be harder. I leave that to you for now

 

[Ichida]

Why is this worth a thread again?

 

[Ichida]

EDIT: More node-related bullcrap. Ignore.

 

[MorpheusVGX]

Does it exist?

 

[InvincibleAgent]

Neat? How about you add stages into that?

 

[Whiteface]

lol

10char

 

[ShumPenPo]

If you want to do math to determine the number of matchups use a permutation/combination its a lot easier, probably why you only have the number of 1v1 matchups there are. If you consider all 39 unique characters and in a 1v1 match you basically choose the number of different combinations of 2 characters out of the 39. C = n!/r!(n-r)! n is the number you have total (39) r is the number of characters your choosing (2). (also if u didnt konw 5! = 5*4*3*2*1). C = 39!/2!37! = 741 so there would be 741 differnt character matchups in 1v1s. Using that formula you can better determine it with stages or with 2v2s rather than logically.

edit: i also forgot to add the fact that your allowing duplicates (same character vs same character) tack on an extra 39 and u get 780 wootz the actual formula for duplicates is escaping me right now -_-

still, why is this a thread >_<

 

[Ichida]

How about we add skill level of each and every player and mastery of each player with each and every character? <.<;

 

[Replacement100]

If you want to do math to determine the number of matchups use a permutation/combination its a lot easier, probably why you only have the number of 1v1 matchups there are. If you consider all 39 unique characters and in a 1v1 match you basically choose the number of different combinations of 2 characters out of the 39. C = n!/r!(n-r)! n is the number you have total (39) r is the number of characters your choosing (2). (also if u didnt konw 5! = 5*4*3*2*1). C = 39!/2!37! = 741 so there would be 741 differnt character matchups in 1v1s. Using that formula you can better determine it with stages or with 2v2s rather than logically.

still, why is this a thread >_<

Was totally gunna say that... looks like the OP just learned about Factorials ^_^

 

[Whiteface]

There's an easy way to do this..... Take the number of chars(N) multiply by the no of match types(M).... and divide by amt of landmasters(?)

 

[Fluke]

Now you want to add the possibilities of special brawl modes? And which items involved (all/none/some)

XDXD

This proves there's a lot more variety for fun brawl. (For competitive, it would be much less)

 

[fr0st2k]

If you want to do math to determine the number of matchups use a permutation/combination its a lot easier, probably why you only have the number of 1v1 matchups there are. If you consider all 39 unique characters and in a 1v1 match you basically choose the number of different combinations of 2 characters out of the 39. C = n!/r!(n-r)! n is the number you have total (39) r is the number of characters your choosing (2). (also if u didnt konw 5! = 5*4*3*2*1). C = 39!/2!37! = 741 so there would be 741 differnt character matchups in 1v1s. Using that formula you can better determine it with stages or with 2v2s rather than logically.

edit: i also forgot to add the fact that your allowing duplicates (same character vs same character) tack on an extra 39 and u get 780 wootz the actual formula for duplicates is escaping me right now -_-

still, why is this a thread >_<

not sure.. its been a while since ive had to do any kind of math. But isnt this including same character matchups ... such as

Mario vs Pikachu
and then
Pikachu vs Mario?

In this case ... the number isnt technically right.

 

[Yigguth]

^Then just half it
390.

 

[ShumPenPo]

not sure.. its been a while since ive had to do any kind of math. But isnt this including same character matchups ... such as

Mario vs Pikachu
and then
Pikachu vs Mario?

In this case ... the number isnt technically right.

if it were a permutation then it wouldnt be right because it would include those matches. The permutation would end up being P = 39!/37! = 1428. But i used a combination which is the same but eliminates those cases becase the order doesnt matter then i added 39 for dittos to get 780.

 

[SSJ4Kazuki]

There's an easy way to do this..... Take the number of chars(N) multiply by the no of match types(M).... and divide by amt of landmasters(?)

This is epic, but yeah I just learned about factorials in math class. What's the point of this thread?

 

[180OP]

how about i write a C program that can do all these calculations?! To throw in the mix...let's include ITEMS!!!

besides it wouldnt make sense to include duplicates.

If A,B,C are constants, how many sums of two terms can you have?

A+B, B+C, A+C

not including B+A, C+B, and C+A because that doesnt make sense.

 

[Idfection]

What are triples?

 

[MorpheusVGX]

If you want to do math to determine the number of matchups use a permutation/combination its a lot easier, probably why you only have the number of 1v1 matchups there are. If you consider all 39 unique characters and in a 1v1 match you basically choose the number of different combinations of 2 characters out of the 39. C = n!/r!(n-r)! n is the number you have total (39) r is the number of characters your choosing (2). (also if u didnt konw 5! = 5*4*3*2*1). C = 39!/2!37! = 741 so there would be 741 differnt character matchups in 1v1s. Using that formula you can better determine it with stages or with 2v2s rather than logically.

edit: i also forgot to add the fact that your allowing duplicates (same character vs same character) tack on an extra 39 and u get 780 wootz the actual formula for duplicates is escaping me right now -_-

still, why is this a thread >_<

Ha ha.. hey.. you did some nice math. I forgot those formulas. We need those to determine all possible 4 player match ups.

Also, if you think of it... 780 is also de number of possible 2 man teams. So what do we have.. 780 possible 2 man teams against the same 780 possible 2 man teams. That is 780 X 780 = 608 400. And guess what? If you think of these possible matches, we have considered all possible 4 player combinations. So 608 400 is the number of 4 player possible match ups. It is a huge number. If you think I am wrong, let me know.

 

[MorpheusVGX]

not sure.. its been a while since ive had to do any kind of math. But isnt this including same character matchups ... such as

Mario vs Pikachu
and then
Pikachu vs Mario?

In this case ... the number isnt technically right.

No, we are not doing that. Those are permutations, were the order is important. These are combinations. Follow the logic behind my math and you will see I am no not doing what you say.

 

[gecko8721]

too....much...math

 

[6footninja]

Sorry, im more of a history type of person myself. How about I tell you the history of Brawl instead? hehe

 

[Ichida]

Sorry, im more of a history type of person myself. How about I tell you the history of Brawl instead? hehe

The history of Brawl:

We WAITED. A REALLY long freaking time.

 

[Moustachio]

Gaaaaah Neeerds.....

 

[L-dub-E]

to much effin numbers

all i want to know is

03/09/2008
49.99
39 or 35 i dont care

yall hurting my head........bringing back old memories)

 

[DeliciousCake]

Possibilities of all matches with all different types of items on/off in conjunction with stages, brawl modes, and number of players is easily over 9000. 'Nuf said.

 

[T.U.C.]

sso you must count all character on all stages on 2vs2 matches 1vs1 matches 1vs2 matches 1vs3 matches with all items one by one and combinations and all giant-meta(you know what i mean)combinations, coin stock or time matches (time minutes and stock lives), handicap

uh... did i forget something

it's over 9000!!

 

[MorpheusVGX]

If you want to add the stages into the mix, it is the number of stages n X 608 400 and that's it XD

 

[Whiteface]

lol..... Why would someone bump this???

 

[BOTA]

wow, i am totally learning about all these jahnts in math right now, please dont bring this into video games

 

[tafutureboy]

9,001 possible matches

*wait for it*

 

[Chro]

Lol I'm reviewing Probability and Counting right now. Aren't these Permutations, b/c order matters?

 

[Chaosblade77]

For 1vs1 matches, it would be each character vs each character. So, if you have 39 characters, wouldn't that be 39^2? Then you would divide that by two to cut the double matches (Mario vs Link/Link vs Mario).

That leaves you at (39^2) / 2

Now add in stages. Take the above and make each match an option on all 41 stages. That would mean 41 different options for each match up, so just multiply by 41.

Now we are at 41((39^2) / 2)

For anyone interested, that would be other 30,000 match ups, just for two characters with each stage factored in. Of course I haven't done any real math in ages so that might not be right...

 

[25%Cotton]

actually you just do 39x39.......

assuming character vs. self is acceptable.
**edit: sorry this is really old. also i forgot about link vs mario and mario vs link being "technically" the same.