Someone save me with a Calculus question.

[Corpsecreate]

Find the intergral of SinxCosx / (1 - Cosx).

I've been at it for a loooong time now and I absolutely cannot solve it...someone save me

 

[AltF4]

I have a math thread in the Pool Room, exactly for questions like this!

http://www.smashboards.com/showthread.php?t=113366


A good place to get answers for integral problems is Wolfram:

http://integrals.wolfram.com/index.jsp

Type your problem in there and you get an answer of

Cos[x] + 2*Log[Sin[x/2]]


Hopefully that will give you a push in the right direction. post in the math thread I linked to if you still need help finding that answer.

 

[urfaselol]

u substitution u = 1 - cos x, you can figure out the rest

 

[Corpsecreate]

I really like that site, a lot. I managed to figure it out by myself before rechecking this thread (took me at least a good hour) although I got a different answer to what that site gives I know for sure that my answer is correct. Substituting values and comparing my graph to the graph of Cosx + 2Log(Sin(x/2)) tells me that this answer here is incorrect. Hmmmm... maybe the site isn't too accurate?

 

[blueKarat]

ok so i decided to give this a try (dunno if its right)

after letting u =1-cosx

you get cosx = 1-u

and du = sinx dx

then after the calculus

i get ln(1-cosx) -1 + cosx

thats not the same answer as the wolfram site, they might have used some kind of trigonometric idenity or something because i see the sin(x/2)

 

[Azua]

USE THE MATH THREAD