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Wait.... what?i'll remember you <3
The top one is messed up, there's no H produced...i need help on my chem hw too plz!!!!
i know the steps to balancing redox reactions, (like split em in half) but i dont know how to like split these ones....
Cl2 + H2O -> OCl- + Cl-
H2O2 + NO2- -> NO3-
yah if ne1 could help me out... im desperate!
They're the exact same thing, just written differently.Um, I don't think those are CH3 or CH2 groups. It's just Cs with H branches. Hexane means 6 carbons total, and 14 hydrogens.
It's not messed up, the protons simply aren't written out.The top one is messed up, there's no H produced...
Same with the second one actually...
First one's easy; Cl2 is being both oxidized and reduced, so the first reaction you want to look at is:Cl2 + H2O -> OCl- + Cl-
H2O2 + NO2- -> NO3-
Yup, these are right. The way you would write the condensed formula for each is as follows (starting with the one on the upper left, then going down, then looking at the ones on the right and going down):Here I did it for you:
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I'm not sure I did everything ok because it's been a while since my last science class.
wellz we went over it today and the teacher wuz like... since its an aqueous solution, theres like water molecules everywhere so its likeThey're the exact same thing, just written differently.
It's not messed up, the protons simply aren't written out.
First one's easy; Cl2 is being both oxidized and reduced, so the first reaction you want to look at is:
Cl2 -> OCl-
When you balance it and all, you get Cl2 + H2O -> 2OCl- + 2e- + 4H+
Next we look at:
Cl2 -> Cl-
After balancing and such, we find that it is:
Cl2 + 2e- -> 2Cl-
Adding the two together, we get for our final equation:
2Cl2+ 2H2O -> 2OCl- + 2Cl- + 4H+
Second one's a little trickier, and it's been a while since I've done a lot of hydrogen peroxide redox to be honest so I can't remember how to completely balance it.
The nitrite part is easy though:
NO2- -> NO3-
When balanced yields: H2O + NO2- -> NO3- + 2e- + 2H+
I cannot seem to get the peroxide to balance properly unfortunately. Are you sure it's H2O2 and not just H2O?
Keep the chem questions coming though!