What Samurai said. LoSSBM is incorrect with his/her statements on 9 hammer manipulation.
Your probability to hit a 9 is 1/7, always. The key to the 9hammer is the following: you CANNOT get a number your received in your last two swings. That being said, when you enter the game, your last two swings are counted to be 1 and 2, thus rather than entering a game with a 1/9th probability of pulling a 9, you have a 1/7th probability.
This does not change and is not affected by a differential of outcomes from multiple numbers.
Pulling 7,8 give you the EXACT SAME odds of hitting a 9 next compared to 4,7 6,3 or ANY combination of numbers. It doesn't freaking matter what exactly your last numbers were.
No numbers can be pulled again for the next two swings, and THAT IS IT.
People try to overcomplicate the hammer. That's just how simple it is.
God, hearing someone use my 2008 username makes it feel even more outdated, lol. I made the name sometime back in middle school - in like 04/05 or something.
In case mine or TUBAN's descriptions aren't simple enough and you need a walkthrough...
CASE 1: Start of Game
Previous two Hammer #s = 2, 1
Possible Hammer #s = 3, 4, 5, 6, 7, 8, 9
Possible Chance of any of those Numbers = 1 in 7
Possible Chance of a 9 = 1 in 7
The Number I Got: 4
Case 2
Previous two Hammer #s = 1, 4
Possible Hammer #s = 2, 3, 5, 6, 7, 8, 9
Possible Chance of any of those Numbers = 1 in 7
Possible Chance of a 9 = 1 in 7
The Number I Got: 9
Case 3
Previous two Hammer #s = 4, 9
Possible Hammer #s = 1, 2, 3, 5, 6, 7, 8
Possible Chance of any of those Numbers = 1 in 7
Possible Chance of a 9 = 0
The Number I Got: 6
At this point my Previous two Hammers would be 9 and 6, but
I died, after respawn I clear out that previous number queue and start fresh.
Case 4: Freshly Respawned
Previous two Hammer #s = 2, 1
Possible Hammer #s = 3, 4, 5, 6, 7, 8, 9
Possible Chance of any of those Numbers = 1 in 7
Possible Chance of a 9 = 1 in 7
The Number I Got: 3