mr.fizwidget
Smash Champion
what is the probability that someone will have the matching birthdays in a room with 30 people?
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It is a lot of Algebraic steps.My teacher said that Calculus is relatively easy, but it is the algebra involved that makes it difficult.
Is that true?
Yep. Thats what I got.Is the answer?9 2 2
I don't know if anyone answered you or even if you still need the answer, but for a group of 30 people it's about 70%what is the probability that someone will have the matching birthdays in a room with 30 people?
You learnt the quotient rule before you learnt the chain rule? I learnt it in the other way around hehe.Am I supposed to use quotient rule, even though the numerator is a constant? And we aren't supposed to use chain rule yet(thats the next chapter.), so are we supposed to do product rule then? I am just a bit lost. :/
Needs to be learned in Algebra 1:I'm taking Honors Algebra 1.
What all needs to be learned here before taking calculus?
I know what's the expression for gravitational attraction between 2 point particles. The mental block I'm having is about integrating a tiny piece of the rod's mass from -infinity to infinity to find the rod's total mass. If I consider my rod to be infinite, then every little force from a non perpendicular angle acting on my point particle should cancel out with the other side of the rod, and here I am again wondering how I can find the rod's mass!
I'm also learning functions, rate of change, and lots of ******** fractions.Needs to be learned in Algebra 1:
-Graphing
-Finding an equation for a line
-Rise over Run
-Factoring
-Different Properties of Foiling
-Collecting Like terms
-"T-Tables"
-Uhh.... there is more I forgot.
Then you move on to Geometry, Algebra 2, Pre-Calculus, and Trigonometry.
Good luck!
I didn't read your post yesterday, but I was able to solve this pretty neatly using a couple of identities. Specifically, I was right saying both sides of my infinite rod would cancel out, but I wasn't aware of the intrinsic relationship between rho, z and r. Here's how I solved it:hey cf=)
i thought of something
lets say this: we can turn it into terms of cosine
when its so far away, you can assume theta is 180, and when at its closest point is 90.
so technically, df = MmuG/r dr
r = zcostheta
then
dr= zsintheta d(theta)
integrate from 180 to 90
multiply by 2
* i think this way will give you an answer. im just not sure if i set up the integral for the trig correctly tho *
Yo I am not looking forward to physics next year..*picture with scary variables*